24x^2-48x+18=0

Solution for 24x^2-48x+18=0 equation:

24x^2-48x+18=0

a = 24; b = -48; c = +18;
Δ = b2-4ac
Δ = -482-4·24·18
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-24}{2*24}=\frac{24}{48}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+24}{2*24}=\frac{72}{48}
=1+1/2
$